Question

Nishant bought an article at 20% discount on MRP, and claims to sell it at profit of 10% of MRP. When Nikhil offered him Rs. 500 banknote, he cheated again by giving him Rs. 125 instead of Rs. 225. Find overall profit% of Nishant.

Answer 1

Answer:

Step-by-step explanation:

Let MRP be 100 %

Then Cost price =100%-20%=80%

     Selling Price = 100%+10%  =110%  

         (Because he claims to sell it at 10% profit on MRP which is 100% )

He would have  returned Rs. 225

as per his claims (that he earns 10% profit on MRP .)

So

110% of MRP should be = 500 -225 =Rs. 275

But He actually took = 500-125 =Rs. 375

=>> 100% of MRP  = (275/110)*100

                               = Rs. 250   = MRP

then cost price =80% of MRP

                           =80%Rs. 250

                            = Rs. 200

That means Nishant bought the article at Rs. 200

but he sold it at Rs. 375

so actual profit  = 375-200

                             =Rs. 175

profit percentage   =

                                $\frac{ Actual Profit }{Cost Price} \times100 \% \\\\=\frac{175}{200} \times 100\\\\=87.5 \%$

Answer 2

Answer:

Step-by-step explanation:

Nikhil gave Rs. 500 note, & Nishant have to actually pay him Rs.

225. Hence Nishant sold it at Rs. 500 – 225 = 275 to Nikhil.

Now, Let MRP is 100x.

If he will get 10% profit, then SP will becomes 110x.

110x = 275

x = 5.5

∴ MRP is Rs. 250

And CP for Nishant is 80

100

× 25 = Rs. 200.

He got Rs. (500 – 125)

= Rs. 375 from Nikhil.

Hence Profit % = (

375–200

200 ) × 100

=

7

8

× 100 = 87.5%