Math, asked by mohanishmandavi629, 8 months ago

Nishant walks 30 meter in the north direction, after that he took a right turn and walks 40 meter. After that he took a right turn and walks 40 meter more and finally he took a right turn and stop after walking 40 meter. Find the distance of nishant from the initial position?

Answers

Answered by yameenazamkhan
1

Answer:

150m is the answer

Step-by-step explanation:30m+40+40m+40m=150m(total distance covered by nishant)

as... distance is the total length of path covered by an object from the initial position to final position

Answered by ananya4058
0

Answer:

Initial position:A

FINAL POSITION:E

CD=BE=40m

So distance from A to E

=BE-BA

=40m-30m

=10m

Therefore distance of Nishant from initial position is 10m.

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