NITA WALKS FROM HER HOUSE 160 METERS NORTH AND FROM THERE 630 METER WEST TO VISIT HER FRIEND . WHILE COMING BACK , SHE WALKED DIAGONALLY FROM HER FRIEND'S HOUSE BACK TO HER HOME . WHAT DISTANCE DID SHE WALK BY COMING BACK ?
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QUESTION :-
Nita walks from her house 160 meters north and from there 630 meter west to visit her friend . while coming back , she walked diagonally from her friend's house back to her home . what distance did she walk by coming back ?
ANSWER :-
650 m
STEP BY STEP SOLUTION:-
( see the figure )
According to question we have to find = SF
OF = 630 m
OS = 160 m
SF = ?
By Applying Pythagoras Theorem ,
SF² = OS² + OF²
SF² = 160² + 630²
SF² = 25600 + 396900
SF² = 422500
SF = 650 m
So , distance Nita walk while coming back =
650m
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QUESTION :-
Nita walks from her house 160 meters north and from there 630 meter west to visit her friend . while coming back , she walked diagonally from her friend's house back to her home . what distance did she walk by coming back ?
ANSWER :-
650 m
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