Nitin walks at 3/4 of his usual speed and reaches his home 10 minutes late, find the usual time taken by him to reach his home.
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Given New speed = (3/4) of his usual speed.
We know that Speed and time are inversely proportional.
Then, New time = (4/3) of his usual time.
Hence,
= > (4/3 of usual time) - (usual time) = 10
(4/3) - 1 = > (4 - 3)/3 = > 1/3.
= > (1/3) of usual time = 10
= > Usual time = 30
Therefore, the usual time taken by him to reach his home = 30 minutes.
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