Math, asked by spidy9564, 1 month ago

Nitin wants to construct a rectangular plastic tank for his house that can hold 80 ft 3 of water. The top of the tank is open. The width of tank will be 5 ft but the length and heights are variables. Building the tank cost Rs.20 per sq. foot for the base and Rs.10 per sq. foot for the side​

Answers

Answered by amitnrw
21

Given : The top of the tank is open. The width of tank will be 5 ft but the

length and heights are variables.

Building the tank cost 20 per sq. foot for the base and 10 per sq. foot for the side.

Volume of tank is 80 cubic ft  

To Find : In order to make a least expensive water tank, Nitin need to minimize what ?

Solution:

In order to make a least expensive water tank, Nitin need to minimize  cost

The width of tank will be 5 ft

Let sat  height = h

Volume = length * width * height

=> 80 = 5 *  length * h

=>  length = 16/h

Base area = 5 * 16/h  

CSA  = 2 ( 5 + 16/h) * h

Cost = 20 ( 5 * 16/h  )  + 10 * 2 ( 5 + 16/h) * h

= 1600/h  + 100h  + 320

c(h) = 100h  + 320 +  1600/h

Range of h  (0 , ∞)

c(h) = 100h  + 320 +  1600/h

=> c'(h)  = 100  - 1600/h²

c'(h)  = 0

=>  1600/h² = 100

=> h = 4

c''(h) = 3200/h³ > 0

Hence cost is minimum at h = 4

The cost of least expensive tank  

c(h) = 100h  + 320 +  1600/h

c(4) = 400 + 320 + 400

= 1120

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