Question

Nitro glycerine is used as an explosive. The equation for the explosive reaction is 4C3H5((NO3 ))3 12CO2 + 10H2O + 6N2 + O2 ( l ) ( g ) ( l ) ( g ) ( g) (Atomic mass of C = 12, H = 1, N = 14, O=16) i) How many moles does the equation show for i) Nitroglycerine ii) gas molecules produced? ii) How many moles of gas molecules are obtained from 1 mole of nitroglycerine? iii) What is the mass of 1 mole of nitroglycerine?

Answer 1

Explosive reaction of nitroglycerine is as follows.

4C_3 H_5 ((NO_3 ) )_3  →12CO_2+ 10 H_2 O+6N_2+ O_2

                                          (l)                     (g)               (l)               (g)          (g)                            

a) How many moles does the equation show for

                  i)Nitroglycerine – 4

                  ii) gas molecules produced-19

b) From the equation

                4 moles of Nitroglycerine gives – 19 moles of gases

                1 moles of Nitroglycerine -?

c) Number of moles of gaseous molecules from one mole of Nitroglycerine=  (19 moles)/4=4.75 moles

                 Mass of Nitroglycerine = C_3 H_5 ((NO_3 ) )_3=3(12)+5(1)+3(14)+9(16))

                                                      =36+5+42+144

                                                      =227 g/mol