Question

nitrogen and hydrogen react in the ration 14:3 to form ammonia gas. what mass of hydrogen will be required to react completely with 56 gram of nitrogen?​

Answer 1

Answer:-

12g of Hydrogen is required.

Explanation:-

The balanced chemical equation, for the reaction is :-

N₂ + 3H₂ → 2NH₃

Now, it is given that the mass ratio between Nitrogen and Hydrogen in Ammonia is 14 : 3. [Law of constant/definite proportions] . So, we can understand that in NH₃ ,14g of Nitrogen will always react with 3g of Hydrogen.

∵ 14g N₂ → 3g H₂

∴ 56g N₂ → 56×3/14 = 12g H₂

Thus, 12g of Hydrogen will be required to react completely with 56g of Nitrogen.

Some Extra Information:-

Law of definite proportions : This law was given by Josheph Proust along with Lavoisier.

The law is 'In a chemical substance, the elements are always present in definite proportions by mass' .