Question

Nitrogen combines with dihydrogen according to the reaction. N2(g) + 3H2(g) ⇌ 2NH3(g) What is the ratio in their volumes under similar conditions of temperature and pressure? 6.

Answer 1

In the reaction, N

2

+3H

2

→2NH

3

, the ratio by volume of N

2

, H

2

and NH

3

is 1:3:2. This illustrates the law of Gaseous volumes or Gay Lussac's law of combining volumes of gases.

According to this law, when gases react together to produce gaseous products, the volume of reactants and products bear a simple whole-number ratio with each other, provided volumes are measured at the same temperature and pressure.

$In the reaction, N2+3H2→2NH3, the ratio by volume of N2, H2 and NH3 is 1:3:2. This illustrates the law of Gaseous volumes or Gay Lussac's law of combining volumes of gases.</h3><h3></h3><h3>According to this law, when gases react together to produce gaseous products, the volume of reactants and products bear a simple whole-number ratio with each other, provided volumes are measured at the same temperature and pressure.</h3><h3></h3><h3>$

mark me as brainlist

Answer 2

The relation in their volumes underneath similar conditions of temperature and pressure is 1:3:2

• Since, within the given the magnitude relations of the gases are in easy number ratio
• It is demonstrating the law of aeriform volume. By victimization Gay-Lussac law is valid.
• Gay-Lussac’s law could be a gas law that states that the pressure exerted by a gas (of a given mass and unbroken at a continuing volume) varies directly with absolutely the temperature of the gas. In alternative words, the pressure exerted by a gas is proportional to the temperature of the gas once the mass is mounted and therefore the volume is constant.
• This law was developed by the French chemist Joseph Gay-Lussac in the year 1808.
• The mathematical expression of Gay-Lussac’s law is written as follows:

P ∝ T ; P/T = k

Where:

P is that the pressure exerted by the gas,

T is that the temperature of the gas,

k could be a constant

Formula and Derivation:

• Gay-Lussac’s law implies that the magnitude relation of the initial pressure and temperature is up to the magnitude relation of the ultimate pressure and temperature for a gas of a set mass unbroken at a continuing volume. This formula is expressed as follows:

(P1/T1) = (P2/T2)

Where:

P1 is that the initial pressure

T1 is the initial temperature

P2 is that the final pressure

T2 is the final temperature

• This expression is derived from the pressure-temperature proportion for gas.
• Since P ∝ T for gases of mounted mass unbroken at constant volume:

P1/T1 = k (initial pressure/ initial temperature = constant)

P2/T2 = k (final pressure/ final temperature = constant)

Therefore, P1/T1 = P2/T2 = k

Or,

P1T2 = P2T1

#SPJ2