Question

Nitrogen forms 2 oxides in which mass percentage of oxygen is 63.15% and 74.07% respectively. Write their emperical formulae. I need answer with full and detailed process.​

Answer 1

Answer:

ANSWER

Let us consider a sample containing 100 g NxOy

For N⇒x×14=

100

100×25.94

⇒x=1.85

For O⇒y×16=

100

100×74.09

⇒y=4.63

So, N

1.85

O

4.63

⇒N

2

O

5

(Empirical Formula)

Explanation:

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