Question

Nitrogen laser produces a radiation at a wavelength of 337.1 nm. If the number of photons emitted is 5.6 × 10^24, calculate the power of this laser.


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Answer 1

Answer :

• Power of the laser = $\rm{3.3\times{}10^6\:J}$

Step-by-step explanation :

Given that,

• Wavelength of radiation, λ = 337.1 nm = $\rm{337.1\times{}10^{-9}\:m}$
• No. of photons emitted, N = 5.6 × 10²⁴

Also,

• Planck's constant, h = $\rm{6.626\times{}10^{-34}\:J\:s}$
• Speed of light, c = $\rm{3.0\times{}10^8\:m\:s^{-1}}$

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We know, $\rm{E=\dfrac{Nhc}{\lambda}}$

Putting the given values, we get,

$\rm{E=\dfrac{(5.6\times{}10^{24})(6.626\times{}10^{-34}\:J\:s)(3.0\times{}10^8\:m\:s^{-1})}{337.1\times{}10^{-9}\:m}}$

Solving, we get,

$\rm{E=}\:\bold{3.3\times{}10^6\:J}$

Answer 2

Answer:

Nitrogen laser produces a radiation at a wavelength of 337.1 nm. If the number of photons emitted is 5.6 × 10²⁴, calculate the power of this laser. Hence, the power of the laser is 3.33 × 10⁶ J.