Question

NLM question

Consider the arrangement shown. Table top is rough and coefficient of friction between table top and block 2m is μ. Pulley and string are ideal.

Minimum value of μ at table top to keep system at equilibrium, is

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Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{\mu=0.5}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline{\bold{Given :}}} \\ \tt: \implies Mass \: of \: blocks = m \: and \: 2 m \\ \\ \red{\underline{\bold{To \: Find :}}} \\ \tt: \implies Minimum \: value \: of \: \mu \: so \: that \: system \: will \: be \: in \: equilibrium =?$

• According to given question :

$\bold{For \: block \: of \: mass \: m} \\ \tt: \implies mg - T= ma \\ \\ \tt \because \: a = 0 { \: m/s}^{2} \\ \\ \tt: \implies T = mg - - - - - (1) \\ \\ \bold{For \: block \: of \: mass \: 2m} \\ \tt: \implies T = fr \:\:\:\:\:\:(for\:equilibrium) \\ \\ \tt: \implies T= \mu N \\ \\ \tt: \implies t = \mu \: 2mg \\ \\ \tt: \implies mg = \mu \: 2mg \\ \\ \tt: \implies \mu = \frac{mg}{2mg} \\ \\ \green{\tt: \implies \mu = 0.5} \\ \\ \green{ \tt \therefore Minimum \: coefficient \: of \: friction \: is \: 0.5 }$

Answer 2

Explanation:

$\huge\bold{\underline{\underline{\red{Global\:warming}}}}$

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