Question

No. 11
11. Perimeter of square whose length of the diagonal 6root 2cm is
a) 28
b) 24
c) 20
d) 32​

Answer 1

Answer:

Given :-

Diagonal of square = 6 √2 cm

To Find :-

Perimeter

SoluTion :-

We know that

$\star \large \sf \: Diagonal = \sqrt{2} \times side$

$\large \sf \to \: 6 \sqrt{2} = \sqrt{2} \times s$

$\large \sf \to \: \dfrac{6 \cancel{\sqrt{2}} }{ \cancel{ \sqrt{2}}} = s$

$\large \sf \to \: 6 = s$

Now,

$\star \large \sf \: Perimeter = 4s$

$\large \sf \to \: Perimeter = 4(6)$

$\large \sf \to \: Perimeter \: = 24 \: cm$

Answer 2

Answer:

diagonal=6√2

by the Pythagoras theorem,

a^2+ a^2= 6√2^2

2a^2= 36*2

2a^2= 72

a^2 = 72/2

a^2 36

a=√36

a=6

perimeter of the square =4*side

=4*6=24cm

hope it's useful for you