Question

No 2 please solve iit

Answer 1

Answer:

-0.591V

Explanation:

using formula (H+) =10 _ph

so H + = 10-10 M

use the formula

value of E0 = 0

E cell = E0 -0.591/1 log(H2) /H+

E cell= 0.591 /1 log (1/10-10 )

E cell = 0.591/1(10) =-0.591V