No.51 . Its a challenge !!!can u solve it ?? Dont comment anything vulgar.
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ironman30:
i had two congurence but not getting third one
would like to know the congurence
I want to know the third one
I know the rest two
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AB=CD because in a rectangle opp pairs of sides are equal.
<1+<=<4+<2
<1+<3=<4+<1. (<1=<2 (AA)
<3=<4
AB= CD (GIVEN)
<AEB=<DFC ( 90°)
<3=<4 (proved)
so by ASA CONGRUENCE RULE
tri ABE =~ tri DCF
<1+<=<4+<2
<1+<3=<4+<1. (<1=<2 (AA)
<3=<4
AB= CD (GIVEN)
<AEB=<DFC ( 90°)
<3=<4 (proved)
so by ASA CONGRUENCE RULE
tri ABE =~ tri DCF
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what is your name
Sàmbit patra
Not that politician of bjp
you are biy
What is biy?
I'm a boy from India
which state
Please i request you give your no.
Haryana
please mark brainliest
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hope this may help you
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