Question

No. 8 and 9 ..
If u don't know both the sums and only one then also please answer at least one .

Answer 1

8,11,13,15,x+1,×+3,39,35,40,43

here no of terms are 10 so median would be mean of 5th and 6th terms
$\frac{x + 1 + x + 3}{2} = 22 \\ \frac{2x + 4}{2} = 22 \\ 2x + 4 = 44 \\ 2x = 40 \\ x = 20$

9. 12,14,17,20,22,x,26,28,32,36

here no of terms are 10 so median would be mean of 5th and 6th terms

$\frac{22 +x }{2} = 23 \\ 22 + x = 46 \\ x = 46 - 22 \\ x = 24$

now 32 is replaced by 23 then the data would be
12,14,17,20,22,23,24,26,28,36
new median would be the mean of 22 and 23

$new \: median = \frac{22 + 23}{2} = \frac{45}{2} = 22.5$

Answer 2

answer of 8th answer of 9th

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