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Answers
Heya dost....koi doubt ho to btana....
Given,
Mg =20.0%, S = 26.66%, O = 53.33%
Suppose 100 g of the compound is present. This changes the percents to grams:
Mg = 20 g , S = 26.66 g , O = 53.33 g
Convert the masses to moles
Mg = 20/24 = 0.8333moles , S = 26.66 / 32 = 0.8331 moles, O = 53.33/16 = 3.3331 moles
Divide by lowest number of moles
Mg = 0.8333/0.8331 = 1
S = 0.8331/0.8331 = 1
O = 3.3331 / 0.8331 = 1
Hence, empirical formula = MgSO4
Empirical formula mass = 120.
Molecular mass= 120.
Hence, molecular formula = MgSO4
As crystalline salt on becoming anhydrous loses 51.2% by mass, this means
48.8 g of anhydrous salt contains H2O = 51.2g
Therefore, 120g of anhydrous salt contains H2O = (51.2/48.8) x 120 = 126 g
Number of molecules = 126/18 = 7 molecules
Hence, Molecular Formula of crystalline salt = MgSO4.7H2O
@skb
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