Question

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Answer 1

Explanation:

Assume 100 moles.

After dissociation:

80 mol N2O4

40 mol NO2

PV = nRT ==> V = nRT/P

V1 = (80)(0.082)(300)/1 => V1 = 1968 L * (m^3/1000 L) = 1.968 m^3

V2 = (40)(0.082)(300)/1 => V2 = 984 L * (m^3/1000 L) = 0.984 m^3

m1 = 80 mol * (0.092011 kg/mol) = > m1 = 7.36 kg

m2 = 40 mol * (0.0460055 kg/mol) => m2 = 1.84 kg

ρ1 = 7.36 kg / 1.968 m^3 => 3.74 kg/m^3

ρ2 = 1.84 kg / 0.984 m^3 => 1.87 kg/m^3

ρm = (ρ1V1 + ρ2V2)/(V1 + V2)

ρm = (3.74*1.968 + 1.87*0.984)/(1.968+0.984)

ρm = 3.12 kg/m^3

Answer 2

✔✔Here is your answer in the attachment ✔✔