Question

❌❌NO COPIED ANSWER❌❌

❌❌NO SPAM❌❌

❌❌NEED DETAILED ANSWERS❌❌​

Answer 1

✔✔Here is your answer in the attachment ✔✔

Answer 2

Initial volume, V1 = 100.0l = 100.0 × 10 –3 m3
Final volume, V2 = 100.5 l = 100.5 ×10 –3 m3
Increase in volume, ΔV = V2 – V1 = 0.5 × 10–3m3
Increase in pressure, Δp = 100.0 atm = 100 × 1.013 × 105 Pa
Bulk modulus = Δp / (ΔV/V1)  =  Δp × V1 / ΔV
= 100 × 1.013 × 105 × 100 × 10-3 / (0.5 × 10-3)
= 2.026 × 109 Pa
Bulk modulus of air = 1 × 105 Pa
∴ Bulk modulus of water / Bulk modulus of air  =  2.026 × 109 / (1 × 105)  =  2.026 × 104
This ratio is very high because air is more compressible than water.
HOLA DEAR ✨✨
PLEASE MARK AS BRILLIANT

FOLLOW ME