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A bus starts from rest and moves with a uniform acceleration of 1m/sec^2 for five minutes. calculate the speed acquired and the distance travelled by the bus.
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Hlo friend.. Cutiepie Here..
Here is ur answer :
Initial velocity u = 0 ( starts from rest)
Acceleration a = 1 m/ s²
Time t = 5 minutes = 300 s
We have to find final velocity.
Let final velocity be v
From Ist equation of motion,
v = u + at
v = 0 + 1 × 300
v = 300 m/s
Speed acquired by bus = 300 m/s.
_____________________
Distance travelled by bus
Let the distance be s.
From IInd eqⁿ of motion,
s = ut + 1/2 at²
s = 0 × 300 + 1/2 × 1 × 300 × 300
s = 150 × 300
s = 45000 m
Distance travelled by bus = 45000 m= 45 km
_________________
HOPE IT HELPS YOU..
Here is ur answer :
Initial velocity u = 0 ( starts from rest)
Acceleration a = 1 m/ s²
Time t = 5 minutes = 300 s
We have to find final velocity.
Let final velocity be v
From Ist equation of motion,
v = u + at
v = 0 + 1 × 300
v = 300 m/s
Speed acquired by bus = 300 m/s.
_____________________
Distance travelled by bus
Let the distance be s.
From IInd eqⁿ of motion,
s = ut + 1/2 at²
s = 0 × 300 + 1/2 × 1 × 300 × 300
s = 150 × 300
s = 45000 m
Distance travelled by bus = 45000 m= 45 km
_________________
HOPE IT HELPS YOU..
Cutiepie93:
if it helps you so pls click on thank you
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