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hi dear
Step-by-step explanation:
etna hi solve hua h , lgta h jada high level ka h ,,, mere aage kuch smj nhi aa rha h ,
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6 x +4 x =9 x
divide by 4 x to form ( 23 ) x4 x6 x +1= 4 x9 x( 23 ) x +1=( 23 ) 2x(( 23 ) x ) 2 −( 23 ) x −1=0
So ( 23) x = 21± 1−4.1(−1) = 21±, 5
For positive solution( 23 ) x= 21+ 5
Applying logarithmxln( 23 )=ln( 21+ 5 )
xln( 23 )=ln( 21+ 5 )ln ba=lna−lnbx= ln3−ln2
ln(1+ 5 )−ln2
x= ln3−ln2ln(1+ 5 )−ln2
Step-by-step explanation:
Solve by adaptor
Hope it helps!!
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