Physics, asked by supriyapujahari4, 7 months ago

No irrelevant answers please

Find the dimensional formula of
●Permittivity of free space
●Universal gas constant
●Magnetic flux

Give correct answers please ​

Answers

Answered by triptiroymondal
1

Explanation:

Permittivity of free space ϵ

o

=

4πFr

2

q

1

q

2

Dimensions of [F]=[MLT

−2

]

Dimensions of [q]=[AT]

Dimensions of [r]=[L]

Thus dimensional formula of [ϵ

o

]=

[MLT

−2

][L

2

]

[AT][AT]

⟹ [ϵ

o

]=[M

−1

L

−3

T

4

A

2

]

Answer By

Answered by Anonymous
11

Answer:

●Permittivity of free space:

the permittivity of free space or vacuum is dimensionally represented as M1 L-3 T4 I2.

●Universal gas constant :

Or, G = [M^1 L^-1 T^-2] × [M^0 L^3 T^0] × [M^0 L^0 T^0 K^1]-1 = [M^1 L^2 T^-2 K^-1]. Therefore, the Universal Gas Constant is dimensionally represented as [M^1 L^2 T^-2 K^-1].

●MAGNETIC FLUX:

B = Magnetic Field, A = Surface Area, and θ = Angle between the magnetic field and normal to the surface. Therefore, Magnetic Flux is dimensionally represented as [M^1 L^2 T^-2 I^-1].

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