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63/64is the required answer.
Now,this is the correct answer
We have,
p(x)=x^6-1
By remainder theorem,we know that,if p(x)is divided by x-a,then p(a) is the remainder.
So, when P(x) is divided by 2x+1,then p(-1/2) is the remainder.
So,
p(-1/2)=(-1/2)^6-1
=1/64-1=-63/64
Now,The absolute value of -63/64 is 63/64.
Additional information-
The absolute value of a number is the non-negative value of that number.
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