Question

no. of atom in 2.3g of sodium

Answer 1

23g of sodium has 6.022 × 10^23 atoms 2.3g of sodium has {(6.022 × 10^23) / 23} × 2.3 = 6.022 × 10^22 atoms

Answer 2

Answer:

$6.023 X 10^{22} atoms$

Explanation:

23 g of Na = 1mole of Na

2.3 g of Na = ? mole of Na

2.3/23 = 0.1 mole of Na

1 mole of Na = 6.023 x 10^23 atoms

0.1 moles of Na = ? atoms

6.023 x 10^22 atoms