Question

No. of atoms in 4.25 g. of NH3
, is approx :-
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Answer 1

So 4.25 g ammonia will contain (6.022×10^23×4.25)/17 = 1.5×10^23 number of ammonia molecules. Each molecule contain 4 atoms (1 N atom and 3 H atoms). So 4.25g ammonia will contain 1.5×10^23×4 = 6×10^23 number of atoms