no. of atoms in 4.25g of NH3
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Answered by
3
Answer:
1.5*10^23
Explanation:
avagadro no*given compound (GM)/ molecular weight
6.022*10^23*4.25/17=1.5*10^23
Answered by
1
17gm NH3=NA molecules ....
4.25g=(NA/17)*4.25 molecules...
Number of atoms = 4*(NA/17)*4.25 atoms..
Thus the answer will be ....
NA atoms i.e. 6.022*10^23
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