no.of atoms in 4.25g of NH3 is
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Answered by
7
Dear student..
Molar mass NH3 = 14+3 = 17g/mol
given mass = 4.25g
no of moles = 4.25/17 = 0.25 mol of NH3
1 mol of NH3 contains 6.022*10^23 molecules
0.25 mol NH3 contains 0.25*6.022*10^23 = 1.5055*10^23 molecules
1 molecule of NH3 contains 4 atoms
Number of atoms in 1.5055*10^23 molecules = 4*1.5055*10^23 atoms.
The correct answer is = 6.022*10^23 atoms.
Molar mass NH3 = 14+3 = 17g/mol
given mass = 4.25g
no of moles = 4.25/17 = 0.25 mol of NH3
1 mol of NH3 contains 6.022*10^23 molecules
0.25 mol NH3 contains 0.25*6.022*10^23 = 1.5055*10^23 molecules
1 molecule of NH3 contains 4 atoms
Number of atoms in 1.5055*10^23 molecules = 4*1.5055*10^23 atoms.
The correct answer is = 6.022*10^23 atoms.
Answered by
0
Answer:
Molar mass of NH3 = 17g
No of moles = 4.25/17 moles
=1/4moles
1moles of NH3 = 6.10²³ (approximate)
1/4moles of NH3 = 1/4 ×6×10²³
=3/2 .10²³
4 atoms is equal to 4.3/2.10²³
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