No of atoms present in 11.2 l of chlorine at stp
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1 mole occupies 22.4 litre at stp
thus 11.2 litres contains =11.2/22.4 = 0.5 moles
1 mole contains 6.023 * 10^23 molecules
thus 0.5 mole contains= 0.5 *6.023*10^23=3.0115*10^23 molecules
1 molecule contains 2 atoms
3.0115*10^23 molecules contain=2*3.0115*10^23=6.023 * 10^23 atoms!
hope this helps!
thus 11.2 litres contains =11.2/22.4 = 0.5 moles
1 mole contains 6.023 * 10^23 molecules
thus 0.5 mole contains= 0.5 *6.023*10^23=3.0115*10^23 molecules
1 molecule contains 2 atoms
3.0115*10^23 molecules contain=2*3.0115*10^23=6.023 * 10^23 atoms!
hope this helps!
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