No. of atoms present in 16g of Ozone (O3).
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1
heyshiv:
nope, it's 6.023*10^23*0.3*3
0.3*6.022*10^23
if it would have been no. of molecules then we would have not multiplied it by 3
But as no. of molecules we'll multiply by 3
atoms*
48gof ozone=1mole=6.022*10power23molecules is ozone=3*NAatoms of oxygen no of oxygenation in 1g of ozone =3*NAatoms of oxygen48no. of oxygen atom in 16g of ozone =3*NA atoms of oxygen 48x16=NA
NA atoms
you answered rubbish
We can multiply 3 in the starting itself with 16 to make O3
for Ozone
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0
No. of moles - Given mass / molar mass
No. of moles = 16 /48 = 0.3
Here Given mass of is 16g and molar mass or molecular mass is 48
No. of moles = 16 /48 = 0.3
Here Given mass of is 16g and molar mass or molecular mass is 48
Incomplete.
Sorry, I thought only moles
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