Question

no. of atoms present in 2gm of calcium

Answer 1

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Here is your answer... ✌
Molar mass of calcium = 40 g
Number of moles in 2 g calcium = mass/molar mass
= 2/40 = 0.05

Number of atoms in 1 mole of calcium = 6.022 x 1023
Number of atoms in 0.05 moles of calcium = 0.05 x 6.022 x 1023
= 3.011 x 1022

Answer 2

GAM of Ca = 40 g
No. of atoms in 40 g of Ca =
$6.022 \times {10}^{23}$
No. of atoms in 2 g of Ca
$= \frac{6.022 \times {10}^{23} \times 2}{40} = 3.011 \times {10}^{24}$