Question

No. of atoms present in 46g of sodium

Answer 1

Answer:

There are 1 moles in 23g of Sodium.

So there will be 2 moles in 46g of Sodium.

No. of atoms in 23g of Sodium = No. of moles * Avogadro Number

No. of atoms in 46g of Sodium = 2(No. of moles * Avogadro Number)

= 2( 1 * 6.022*10^{23}) = 12.044 * 10^23 Atoms

Hope it helps !

Peace ✌

Answer 2

Answer:

12.044 ×10²³ atoms..

Explanation:

since 1 mole 6.022×10²³ is 23 grams 22.99actually which is rounded of to 23 2 moles 46 grams will have 2×6.022×10²³= 12.044×10²³