No. Of Carbon atoms in 2.8 g of carbon monoxide
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Answered by
1
Molecular weight of CO=28g
So,28g of CO contain =12g of carbon
So, 2.8g of CO contain=(2.8\12)×28=1.2 carbon
12g of carbon=6.023×10^23
So, 12g=(6.023×10^23×1.2)\12
=6.023×10^22
So,28g of CO contain =12g of carbon
So, 2.8g of CO contain=(2.8\12)×28=1.2 carbon
12g of carbon=6.023×10^23
So, 12g=(6.023×10^23×1.2)\12
=6.023×10^22
Answered by
0
moles of CO=0.1
since one mole of CO has avagadro number of atoms of C.
so 0.1 has 0.1x6.02x10^23 atoms.
. =6.02x10^22
since one mole of CO has avagadro number of atoms of C.
so 0.1 has 0.1x6.02x10^23 atoms.
. =6.02x10^22
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