no. of coulomb required to reduced to 0.02 mole of benzaldehyde to benzyl alcohol? how ans is 3860c?
Answers
Answer:
KINDLY MARK ME AS BRAINLIEST IF U LYK IT
Explanation:
n this reaction , Reaction for reduction
__________________________
C₆H₅NO₂ +6H⁺ +6e⁻ -----→ C₆H₅NH₂ +2H₂O
__________________________
Given in the question :-⇒
Molar mass of nitrobenzene =123
Here 12.3 nitrobenezene Mole= 6×12.3 / 123
= 0.6
Charge = 0.6 × 96500
=57900
As 50% efficiency
So, 2 × 57900
=115800 C .
Answer:
number of coulombs required = 3860 c
Explanation:
c6h5 -cho + H2 -> c6h5- ch2oh
number of grams of h2 required to reduce 1 mole of c6h5-cho = 2g
number of grams of h2 required to reduce 0.02 mole of c6h5-cho = 0.04g
from faradays first law m = Mct / nF
Where m = mass of the gas to be liberated = 0.04g
M = molecular weight of gas = 2g
t = time here let time = 1 sec
n = number of electrons involved = 2 c = no. of coulombs
F = faraday = 96,500 c
by substituting the values 0.04 = 2 x c x 1 / [2 x 96500]
finally we get number of coulombs = 3680 c