Question

no. of diagonals for polygons of 4to 10 sides

Answer 1

The number of diagonals of a n sided

polygon is
$\frac{n(n - 3)}{2}$
if n=4 , then 2 diagonals


if n=10, then 35 diagonals

Answer 2

Here is your answer hope it helps plz mark it as brainliest ☺☺
We can find number of diagonal in a polygon by the formula n(n-3)/2 i.e if 4 sided polygon then 4(4-3)/2=2diagonals and for pentagon 5(5-3)/2=5 diagonal hexagon will have6(6-3)/2=9 diagonals and heptagon will have7(7-3)/2=1 4 diagonals and 8sided polygons will have 8(8-3)/2=20 diagonal and 9sided polygon will have9(9-3)/2=27 diagonals and polygons with 10sides will have10(10-3)/2=3 5 diagonals......