no. of diagonals in a hexagon
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Number of diagonals of a n-sided polygon is n(n-3)/2
Hexagon has 6 sides.
So number of diagonals in a hexagon =6(6-3)/2=6*3/2=18/2=9 diagonals
Hexagon has 6 sides.
So number of diagonals in a hexagon =6(6-3)/2=6*3/2=18/2=9 diagonals
Answered by
4
n(n-3)/2 Is the diagonal of n sided polygon
6(6-3)/2 Is the no. Of diagonals of hexagon
= 18/2
= 9
6(6-3)/2 Is the no. Of diagonals of hexagon
= 18/2
= 9
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