No. Of electrons in 0.2 mol of al3+ ion is
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4
we know, atomic number of aluminium is 13. so, number of electrons in Al = 13
because , Al^3+ ion forms when we remove three electrons from Al atom.
so, number of electrons in Al^3+ ion = 10
given, number of mole of Al^3+ ion = 0.2
so, number of Al^3+ ions = 0.2 × Avogadro's number
= 0.2 × 6.023 × 10²³
= 1.2046 × 10²³
now, number of electrons in 1.2046 × 10²³ Al^3+ ions = 10 × 1.2046 × 10²³
= 1.2046 × 10²⁴
hence, number of electrons in 0.2 mol of Al^3+ ion is 1.2046 × 10²⁴
Answered by
0
Answer:
The Answer is 2.
Explanation:
1 mole of =10* electrons
Where,
= Avogadro's Number
=10*
=1024 electrons
For 0.2 mole of = 0.2**10
=0.2* electrons
=2
#SPJ2
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