Question

No. Of electrons in 0.2 mol of al3+ ion is

Answer 1

we know, atomic number of aluminium is 13. so, number of electrons in Al = 13

because , Al^3+ ion forms when we remove three electrons from Al atom.

so, number of electrons in Al^3+ ion = 10

given, number of mole of Al^3+ ion = 0.2

so, number of Al^3+ ions = 0.2 × Avogadro's number

= 0.2 × 6.023 × 10²³

= 1.2046 × 10²³

now, number of electrons in 1.2046 × 10²³ Al^3+ ions = 10 × 1.2046 × 10²³

= 1.2046 × 10²⁴

hence, number of electrons in 0.2 mol of Al^3+ ion is 1.2046 × 10²⁴

Answer 2

Answer:

The Answer is 2$N_{A}$.

Explanation:

1 mole of $Al^{3+}$ =10*$N_{A}$ electrons

Where,

$N_{A}$ = Avogadro's Number

     =10*$\frac{23}{24}$$N_{A}$

     =10$N_{A}$24 electrons

For 0.2 mole of $Al^{3+}$ = 0.2*$N_{A}$*10

                                   =0.2*$10^{24}$ electrons

                                   =2 $N_{A}$

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