Chemistry, asked by lakshaycool200016, 1 year ago

No. Of electrons in 0.2 mol of al3+ ion is

Answers

Answered by abhi178
4

we know, atomic number of aluminium is 13. so, number of electrons in Al = 13

because , Al^3+ ion forms when we remove three electrons from Al atom.

so, number of electrons in Al^3+ ion = 10

given, number of mole of Al^3+ ion = 0.2

so, number of Al^3+ ions = 0.2 × Avogadro's number

= 0.2 × 6.023 × 10²³

= 1.2046 × 10²³

now, number of electrons in 1.2046 × 10²³ Al^3+ ions = 10 × 1.2046 × 10²³

= 1.2046 × 10²⁴

hence, number of electrons in 0.2 mol of Al^3+ ion is 1.2046 × 10²⁴

Answered by aryanagarwal466
0

Answer:

The Answer is 2N_{A}.

Explanation:

1 mole of Al^{3+} =10*N_{A} electrons

Where,

N_{A} = Avogadro's Number

     =10*\frac{23}{24}N_{A}

     =10N_{A}24 electrons

For 0.2 mole of Al^{3+} = 0.2*N_{A}*10

                                   =0.2*10^{24} electrons

                                   =2 N_{A}

#SPJ2

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