no of electrons in 3 g of h3po4
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3×Na/3×1 + 30 + 64 = 18×10^23/97
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Molar mass = 3×H + 1×P + 4×O
= 3+31+64
= 98
No of moles in 3g = 3/98 = 0.03
1 mole of any molecule have 6.022×10^23 electrons/protons/atoms.
So, in 3/98 mole number of electron =6.022×10^23 × 0.03
=1.84×10^22.
Answer = 1.84×10^22
= 3+31+64
= 98
No of moles in 3g = 3/98 = 0.03
1 mole of any molecule have 6.022×10^23 electrons/protons/atoms.
So, in 3/98 mole number of electron =6.022×10^23 × 0.03
=1.84×10^22.
Answer = 1.84×10^22
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