Question

No of electrons involved in the reduction of nitrate ion to hydrazine

Answer 1

Answer:

Oxidation value of each N atom in hydrazine(H2NNH2) is -2 and NO3- it is +5.

Explanation:

(Standard in compounds:H is +1 , O is -2 ,but they stay unchanged.

The difference in oxidation value is (-2) - (+5) = -7 = 7electrons (e-) per N atom (or 14 e- per 2N's in one N2H4.)

So 7 electrons are to be donated to - (and taken or accepted by) one NO3- ion.

oxidator: 2NO3- + 16H+ + 14e- ==> N2H4+6H2O

reductor (donater) :XXX ==> YYY +14e-.