No of electrons present in 4.25g of NH3 gas is ?
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Ello ✌️
here is ur answer...
So 4.25 g ammonia will contain (6.022×10^23×4.25)/17 = 1.5×10^23 number of ammonia molecules. Each molecule contain 4 atoms (1 N atom and 3 H atoms). So 4.25g ammonia will contain 1.5×10^23×4 = 6×10^23 number of atoms.
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Answer:
Explanation:
No of moles = mass÷molar mass
N=4.25÷17
N=0.25
Now,1 mole contain 6•023×10^23 electron
0•25 moles contain 0.25×6.022×10^23 electrons
No of electrons=1.50×10^23
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