Chemistry, asked by kavyasojan2, 1 year ago

No of electrons present in 4.25g of NH3 gas is ?

Answers

Answered by xXHarshuXx
4

Ello ✌️

here is ur answer...

So 4.25 g ammonia will contain (6.022×10^23×4.25)/17 = 1.5×10^23 number of ammonia molecules. Each molecule contain 4 atoms (1 N atom and 3 H atoms). So 4.25g ammonia will contain 1.5×10^23×4 = 6×10^23 number of atoms.

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Answered by palashrajput176
6

Answer:

Explanation:

No of moles = mass÷molar mass

N=4.25÷17

N=0.25

Now,1 mole contain 6•023×10^23 electron

0•25 moles contain 0.25×6.022×10^23 electrons

No of electrons=1.50×10^23

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