Question

no of electrons present in 4.6 g of sodium

Answer 1

no. of atoms×12 is the no. of electrons
moles of sodium=given mass/molecular mass
=4.6/23=0.2moles
no. of atoms in 0. 2 moles =0. 2× 6.022×10^23
no. of electrons =
0.2×6.022×10^23×12
=14.45×10^23 (approximately )

Answer 2

No.Of electrons=no.of moles *6.023*

23

10

4.6g=0.2Moles

0.2*6.023*10power23=

1.2246*10power23