Question

No of eletron and proton in 1.6gram of NaoH

Answer 1

✍Your answer⬇⬇⬇⬇

Moles of NaOH= Given wt./gram mol.wt.

= 1.6/39= 0.04 moles

Now,

No. of electrons =0.04×6.022×10^23×20

= 4.81×10^23

No. of Neutrons

=0.04×6.022×10^23×20

=4.81×10^23

Hope my answer satisfy u dear:)

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