No. Of fe atoms in 100 gm haemoglobin if lt contains 0.33%fe
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Mass of hemoglobin =100 gm
Mass of Fe present =0.33% x 100
=0.33 gm
Atomic mass of Fe =56
Since,
56 gm of Fe contains = 6.022 x 10²³ atoms of Fe
0.33 gm of Fe contains = 6.022 x 10²³/56 x 0.33
=3.548 x 10²¹ atoms of Fe
Hope it helps you
^_^
Mass of Fe present =0.33% x 100
=0.33 gm
Atomic mass of Fe =56
Since,
56 gm of Fe contains = 6.022 x 10²³ atoms of Fe
0.33 gm of Fe contains = 6.022 x 10²³/56 x 0.33
=3.548 x 10²¹ atoms of Fe
Hope it helps you
^_^
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