no.of .Fe atoms present in 100 g of haemoglobin if it contains 0.33%of Fe
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100 g of haemoglobin contains 0.33% i.e. 0.33/100 gm
no of Fe = weight of total Fe/weight of 1 atom of Fe
= 0.33/100÷55.8
= 0.0000564103 ans
I think it is correct.
no of Fe = weight of total Fe/weight of 1 atom of Fe
= 0.33/100÷55.8
= 0.0000564103 ans
I think it is correct.
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