Question

no of girl in families 2. 1. 0
no of families. 475 814. 211

compute the puobablity of a family, chosen at random, having
1) 2girl. 2)1girl. no)girl​

Answer 1

Answer:

Compute the probability of a family, chosen at random, having

(i) 2 girls (ii) 1 girl (iii) No girl

Also check whether the sum of these probabilities is 1.

Solution:

Total numbers of families = 1500

(i) Numbers of families having 2 girls = 475

Probability = Numbers of families having 2 girls/Total numbers of families

= 475/1500 = 19/60

(ii) Numbers of families having 1 girl = 814

Probability = Numbers of families having 1 girl/Total numbers of families

= 814/1500 = 407/750

(iii) Numbers of families having 0 girls = 211

Probability = Numbers of families having 0 girls/Total numbers of families

= 211/1500

Sum of the probability = (19/60)+(407/750)+(211/1500)

= (475+814+211)/1500

= 1500/1500 = 1

Yes, the sum of these probabilities is 1

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Answer 2

Answer:

Number of families having 2 girls =475

Total families =475+814+211=1500

P(2 girls) =

475 / Total families

= 475/1500 = 19/60.

(ii) P(1 girl)= 814/1500. = 407/750.

(iii) P(No girl) = 211/1500

Sum of all these probabilities = 19/60 + 407/750 + 211 /1500.

= 1500 /1500. =

Sum of these probabilities =1

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