Chemistry, asked by aimenbatool2001, 11 months ago

no of gram molecules of oxygen present in 6.02×10∧24 CO molecules is
1
5
2
8
plz ans me as soon as possible

Answers

Answered by Anonymous
2

welcome to the concept of chemistry.

yr answer is 5

⏩6.02 x 10²³ molecules of CO = 1 mole of CO

⏩6.02 x 10²⁴ molecules of CO = 10 mole of CO

= 10 g atoms of O = 5 g molecules of O₂

⏩ I hope it help you ❤️


amritaraj: name??
Anonymous: it is help you
Anonymous: or I explain you this concept in other way?
aimenbatool2001: thank you so much I got it
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Answered by amritaraj
0

Answer:

HEYA MATE

HERE IS ANSWER

✨Number of oxygen atoms = Number of CO molecules = 6.022 x 1024

✨Number of oxygen molecule = 1/2 x Number of oxygen atoms = 1/2 x 6.022 x 1024

= 3.011 x 1024

✨Number of g-molecule of O2 molecules = 3.011 x 1024 /6.022 x 1023 = 5 g-molecule

AND UR ANSWER IS 5


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