Question

no of hybrid orbitals present in propene

Answer 1

No. of hybrid orbitals present in propene?

=> CH2=CH-CH3.

• The 1st and 2nd carbon atoms are in sp2 hybridization as they had to form 3 sigma bonds each.
• The 3rd one had to form all 4 sigma bonds.

Answer 2

Answer:10

Explanation:in propene two carbon atom is SP^2 hybridised and one carbon atom is SP^3 hybridised it means two carbon canten one S and two P charecter (2 carbon×3 charecter=6) and one carbon contain oneS and three P charcter(1carbo×4 charecter=4) thus total no of hybridal orbital is( 6+4=10)