No.of hydrogen atom in 4gm of methane gas is the same as that in
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Molecular weight of hydrogen is 2 and in one hydrogen molecule 2 atoms of hydrogen are present. Hence, no. of atoms present in 4g of H
2
=4/2×2Na=4Na (1)
One molecule of methane contains 4 atoms of Hydrogen. Let amount of methane be
′
x
′
g. Hence, no. of atoms present in
′
x
′
g of CH
4
=x/16×4.Na=x/4.Na (2)
Hence, x/4.Na=4Na (from 1 and 2)
x=16g
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