Question

no of ion pairs in CsCl unitcell

Answer 1

hye guys
CsCl occupies BCC Structured Lattice. 
Cation is at the centre of cube, its contribution to unit cell is 1. 
Number of cations per unit cell  =1×1=1 
Anions are at 8 corners of the cube, each anion is shared by 8 unit cells. 
Contribution to each unit cell is 18. 
Number of anions per unit cell=8corners×18=1 
Therefore, 1 cation and 1 anion per unit cell.

Answer 2

Answer:

Number of ion pairs in CsCl unitcell is 1.

One cation and one anion are present per unit cell of CsCl.

Explanation:

${Cs}^{ + }$is present at the cubic hole and ${Cl}^{ - }$is present at the corners of the cube,froms a simple cubic lattice.

Number of ${Cs}^{ + }$ion per unit cell is 1 and number of ${Cl}^{ - }$ion $= 8 \times \frac{1}{8} = 1$per unit cell.

So,number of ion pairs in CsCl unitcell is 1.