No. of iron atomd in 100g haemoglobin if it contains 0.33% iron
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Mass of Haemoglobin =100 g
Mass of iron atoms = (0.33/100) x 100 =0.33 g
56 g of iron contains = 1 mole of Iron or 6.023 x 1023 atoms
0.33 g of iron contains = (0.33 x 6.023 x 1023)/56 = 3.5492 x 1021 atoms of Fe
Mass of iron atoms = (0.33/100) x 100 =0.33 g
56 g of iron contains = 1 mole of Iron or 6.023 x 1023 atoms
0.33 g of iron contains = (0.33 x 6.023 x 1023)/56 = 3.5492 x 1021 atoms of Fe
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