Question

no of isomers in aromatic compound C8H10 are​

Answer 1

Explanation:

Double bond equivalent =C+1−

2

H

in formula C

8

H

10

,C=8,H=10

D.B.E=8+1−

2

10

=4

there is either 4 double bond or 1 ring- 3 double bond possible or 2 double bond, 2 ring or 2 triple bond etc

C

8

H

10

See Image 1

This is the compound having 4 double bond equivalent

Thus possible structure C

8

H

10

is

See image 2

Thus 5 structural isomers are possible.