No.of molecule of water in a drop of water weighing0.09g are
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Mole=given mass/molar mass
=0.09/18
=0.005 mole
mole=no. of molecules/avogadro number
0.005=no. of molecules×6.022×10^23
0.005/6.022×10^23=no. of molecules
0.00083×6.022×10^23=no. of molecules
0.0049×10^23=no.of molecules
so no. of molecules=4.9×10^20
=0.09/18
=0.005 mole
mole=no. of molecules/avogadro number
0.005=no. of molecules×6.022×10^23
0.005/6.022×10^23=no. of molecules
0.00083×6.022×10^23=no. of molecules
0.0049×10^23=no.of molecules
so no. of molecules=4.9×10^20
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